What is the area of the triangle with vertices $(0, 0)$, $(6, 2)$ and $(2, 5)$?

Explanation

1. 01

   With one vertex at the origin, the determinant reduces to $x_1y_2 - x_2y_1$ for the other two points.

2. 02

   $6(5) - 2(2) = 26$, so the area is $\frac{1}{2} \times 26 = 13$ square units.