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Determinants, Adjoint & Inverse · Question 53 of 87

Question 53

MediumOriginal question

For what value of kk is [k4−28]\begin{bmatrix} k & 4 \\ -2 & 8 \end{bmatrix} a singular matrix?

Options for question 53

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. A matrix is singular when its determinant is 0, and then it has no inverse.

  2. 8k−(4)(−2)=8k+8=08k - (4)(-2) = 8k + 8 = 0 gives k=−1k = -1.

Worth noting

1 comes from 8k−8=08k - 8 = 0: the product (4)(−2)(4)(-2) was taken as +8+8.

Concept
Singular and non-singular matrices
Typical time
90 s
Your time
—
The rule this testsThe adjoint and the inverse
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Ten questions from Determinants, Adjoint & Inverse, at your own pace.

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Ten questions from Determinants, Adjoint & Inverse, at your own pace.