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Determinants, Adjoint & Inverse · Question 44 of 87

Question 44

MediumOriginal question

For Δ=∣13−24052−16∣\Delta = \begin{vmatrix}1 & 3 & -2 \\ 4 & 0 & 5 \\ 2 & -1 & 6\end{vmatrix}, what is the cofactor A32A_{32}?

Options for question 44

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Delete row 3 and column 2: the minor is ∣1−245∣=5+8=13\begin{vmatrix} 1 & -2 \\ 4 & 5 \end{vmatrix} = 5 + 8 = 13.

  2. A32=(−1)3+2×13=−13A_{32} = (-1)^{3 + 2} \times 13 = -13.

Worth noting

13 is the minor; the cofactor carries the sign (−1)i+j(-1)^{i + j}.

Concept
Cofactor of an element
Typical time
90 s
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The rule this testsMinors and cofactors
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Ten questions from Determinants, Adjoint & Inverse, at your own pace.

Practise this chapter →

Ten questions from Determinants, Adjoint & Inverse, at your own pace.