What is the degree of $\frac{d^2y}{dx^2} = \sqrt{1 + \frac{dy}{dx}}$?

Explanation

1. 01

   Clear the root by squaring: $\left(\frac{d^2y}{dx^2}\right)^2 = 1 + \frac{dy}{dx}$.

2. 02

   The highest derivative, $\frac{d^2y}{dx^2}$, is now squared: the degree is 2.