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Chain Rule, Log Differentiation & Rate of Change · Question 10 of 130

Question 10

EasyOriginal question

What is ddx(cot⁡4x)\frac{d}{dx}\left(\cot 4x\right) for 0<x<π40 < x < \frac{\pi}{4}?

Options for question 10

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. ddxcot⁡u=−cosec⁡2u⋅u′\frac{d}{dx}\cot u = -\operatorname{cosec}^{2} u \cdot u' with u=4xu = 4x.

  2. −cosec⁡24x⋅4=−4cosec⁡24x-\operatorname{cosec}^{2} 4x \cdot 4 = -4\operatorname{cosec}^{2} 4x.

Worth noting

−cosec⁡24x-\operatorname{cosec}^{2} 4x forgets the factor 4 from the inside.

Concept
The chain rule
Typical time
60 s
Your time
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The rule this testsThe chain rule
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Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.