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Chain Rule, Log Differentiation & Rate of Change · Question 129 of 130

How fast is the water level rising at the moment the tank holds 18π m³ of water?

Question 129

HardOriginal question

Water is poured at a steady 2 m³/min into a tank shaped like a cone, held vertex down. The tank is 10 m deep and the radius of its top is 5 m. When the water is hh m deep, its surface is a circle of radius rr m.

How fast is the water level rising at the moment the tank holds 18π18\pi m³ of water?

Options for question 129

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. First the depth: πh312=18π\frac{\pi h^{3}}{12} = 18\pi gives h3=216h^{3} = 216, so h=6h = 6.

  2. 2=π×364dhdt=9πdhdt2 = \frac{\pi \times 36}{4}\frac{dh}{dt} = 9\pi\frac{dh}{dt}, so dhdt=29π\frac{dh}{dt} = \frac{2}{9\pi} m/min.

Worth noting

118π\frac{1}{18\pi} m/min uses dVdh=πh2\frac{dV}{dh} = \pi h^{2}, as if r=hr = h.

Concept
A rate of change through a related quantity
Typical time
150 s
Your time
—
The rule this testsRate of change of quantities
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.