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Homogeneous & Linear Differential Equations · Question 111 of 120

Question 111

HardOriginal question

What is the general solution of dxdy+x=y\frac{dx}{dy} + x = y?

Options for question 111

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Linear in xx with P=1P = 1: factor eye^{y}, and ddy(xey)=yey\frac{d}{dy}(xe^{y}) = ye^{y}.

  2. xey=(y−1)ey+Cxe^{y} = (y - 1)e^{y} + C, so x=y−1+Ce−yx = y - 1 + Ce^{-y}.

Worth noting

y=x−1+Ce−xy = x - 1 + Ce^{-x} swaps the roles of xx and yy; here xx is the unknown.

Concept
Solving \(\frac{dx}{dy} + Px = Q\)
Typical time
120 s
Your time
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The rule this testsSolving linear equations
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Ten questions from Homogeneous & Linear Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Homogeneous & Linear Differential Equations, at your own pace.