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Homogeneous & Linear Differential Equations · Question 57 of 120

The solution curve passes through (0, 1).

Question 57

HardOriginal question

Consider the differential equation y ex/y dx=(x ex/y+y) dyy\,e^{x/y}\,dx = (x\,e^{x/y} + y)\,dy, and put x=vyx = vy.

The solution curve passes through (0,1)(0, 1). What is xx when y=ey = e?

Options for question 57

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. At (0,1)(0, 1): e0=log⁡1+Ce^{0} = \log 1 + C, so C=1C = 1.

  2. At y=ey = e: ex/e=1+1=2e^{x/e} = 1 + 1 = 2, so xe=log⁡2\frac{x}{e} = \log 2 and x=elog⁡2x = e\log 2.

Worth noting

log⁡2\log 2 is v=xyv = \frac{x}{y}; xx is vv times y=ey = e.

Concept
A particular solution of a homogeneous equation
Typical time
150 s
Your time
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The rule this testsSolving homogeneous equations
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Ten questions from Homogeneous & Linear Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Homogeneous & Linear Differential Equations, at your own pace.