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Inverse Trigonometric Functions · Question 24 of 120

Question 24

HardOriginal question

What is the range of f(x)=sin⁡−1x+π2f(x) = \sin^{-1} x + \frac{\pi}{2}?

Options for question 24

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. sin⁡−1x\sin^{-1} x runs over [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right].

  2. Adding π2\frac{\pi}{2} shifts it to [0,π][0, \pi].

Worth noting

[π2,π]\left[\frac{\pi}{2}, \pi\right] shifts only the top end.

Concept
The range after a shift
Typical time
120 s
Your time
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The rule this testsDomains and ranges
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.