What is the principal value of cot^-1((√(3))/3)?

Inverse Trigonometric Functions · Question 51 of 120

Question 51

MediumOriginal question

What is the principal value of $\cot^{-1}\left(\frac{\sqrt{3}}{3}\right)$ ?

- \frac{\pi}{3}

Correct answerYour answer

\frac{\pi}{6}

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\frac{\pi}{3}

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\frac{4 \pi}{3}

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Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Find the angle $\theta$ in the branch $(0, \pi)$ with $\cot \theta = \frac{\sqrt{3}}{3}$ .
That angle is $\frac{\pi}{3}$ .

Worth noting

$\cot \frac{\pi}{6} = \sqrt{3}$ ; $\frac{1}{\sqrt{3}}$ is $\cot \frac{\pi}{3}$ .

Ten questions from Inverse Trigonometric Functions, at your own pace.

Ten questions from Inverse Trigonometric Functions, at your own pace.