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Inverse Trigonometric Functions · Question 89 of 120

Question 89

MediumOriginal question

What is the value of cos⁡(sin⁡−135)\cos\left(\sin^{-1} \frac{3}{5}\right)?

Options for question 89

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Let θ=sin⁡−135\theta = \sin^{-1} \frac{3}{5}, so sin⁡θ=35\sin \theta = \frac{3}{5} with θ\theta in [−π2,π2]\left[-\frac{\pi}{2}, \frac{\pi}{2}\right], where cos⁡θ≥0\cos \theta \ge 0.

  2. cos⁡θ=1−925=45\cos \theta = \sqrt{1 - \frac{9}{25}} = \frac{4}{5}.

Worth noting

−45-\frac{4}{5} picks the wrong sign; on the branch of sin⁡−1\sin^{-1} the cosine is never negative.

Concept
A function of a principal value
Typical time
90 s
Your time
—
The rule this testsValues of expressions
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.