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Inverse Trigonometric Functions · Question 120 of 120

Question 120

HardOriginal question

What is the value of cos⁡(2tan⁡−112)\cos\left(2\tan^{-1} \frac{1}{2}\right)?

Options for question 120

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Let θ=tan⁡−112\theta = \tan^{-1} \frac{1}{2}: opposite 1, adjacent 2, hypotenuse 5\sqrt{5}, so cos⁡θ=25\cos \theta = \frac{2}{\sqrt{5}}.

  2. cos⁡2θ=2cos⁡2θ−1=85−1=35\cos 2\theta = 2\cos^{2} \theta - 1 = \frac{8}{5} - 1 = \frac{3}{5}.

Worth noting

45\frac{4}{5} is sin⁡2θ=2tan⁡θ1+tan⁡2θ\sin 2\theta = \frac{2\tan \theta}{1 + \tan^{2} \theta}, the sine of the double angle, not its cosine.

Concept
A function of a principal value
Typical time
120 s
Your time
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The rule this testsValues of expressions
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.