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Linear Programming · Question 52 of 59

Question 52

MediumOriginal question

Which is true of Z=3x+5yZ = 3x + 5y over the region x+y≥2x + y \ge 2, x≥0x \ge 0, y≥0y \ge 0?

Options for question 52

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. The corners are (2,0)(2, 0) and (0,2)(0, 2), where Z=6Z = 6 and 10. The half-plane 3x+5y<63x + 5y < 6 holds no feasible point, so 6 is the minimum.

  2. The region is unbounded upward: (100,0)(100, 0) gives Z=300Z = 300, so there is no maximum.

Worth noting

10 is the value at the other corner, (0,2)(0, 2), not the least.

Concept
No maximum on an unbounded region
Typical time
90 s
Your time
—
The rule this testsUnbounded and infeasible problems
Practise this chapter →

Ten questions from Linear Programming, at your own pace.

Practise this chapter →

Ten questions from Linear Programming, at your own pace.