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Rate of Change, Marginal Cost & Revenue · Question 6 of 79

Question 6

EasyOriginal question

What is the rate of change of the volume of a sphere with respect to its radius when the radius is 2 cm?

Options for question 6

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. dVdr=ddr(43πr3)=4πr2\frac{dV}{dr} = \frac{d}{dr}\left(\frac{4}{3}\pi r^3\right) = 4\pi r^2.

  2. At r=2r = 2: 16π16\pi cm³ per cm.

Worth noting

323π\frac{32}{3}\pi is the volume itself at r=2r = 2, not its rate of change.

Concept
A rate of change with respect to a length
Typical time
60 s
Your time
—
The rule this testsRate of change of a quantity
Practise this chapter →

Ten questions from Rate of Change, Marginal Cost & Revenue, at your own pace.

Practise this chapter →

Ten questions from Rate of Change, Marginal Cost & Revenue, at your own pace.