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Modulo Arithmetic & Congruence · Question 60 of 97

Question 60

HardOriginal question

a≡3(mod5)a \equiv 3 \pmod{5} and b≡4(mod5)b \equiv 4 \pmod{5}. What is (a2+2b) mod 5(a^{2} + 2b) \bmod 5?

Options for question 60

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Replace aa and bb by their remainders: a2+2b≡32+2×4=17(mod5)a^{2} + 2b \equiv 3^{2} + 2 \times 4 = 17 \pmod{5}.

  2. 17=5×3+217 = 5 \times 3 + 2, so the answer is 2.

Worth noting

7 squares nothing: 3+4=73 + 4 = 7 adds the remainders.

Concept
Combining two congruences
Typical time
120 s
Your time
—
The rule this testsCongruence modulo n
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Ten questions from Modulo Arithmetic & Congruence, at your own pace.

Practise this chapter →

Ten questions from Modulo Arithmetic & Congruence, at your own pace.