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Modulo Arithmetic & Congruence · Question 59 of 97

Question 59

MediumOriginal question

Assertion (A): 210≡1(mod11)2^{10} \equiv 1 \pmod{11}.

Reason (R): 25=32≡−1(mod11)2^{5} = 32 \equiv -1 \pmod{11}.

Options for question 59

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. R: 32=33−132 = 33 - 1, and 11∣3311 \mid 33. True.

  2. Squaring R: 210=(25)2≡(−1)2=12^{10} = (2^{5})^{2} \equiv (-1)^{2} = 1, so A is true and follows from R.

Concept
Congruence to a negative number
Typical time
90 s
Your time
—
The rule this testsCongruence modulo n
Practise this chapter →

Ten questions from Modulo Arithmetic & Congruence, at your own pace.

Practise this chapter →

Ten questions from Modulo Arithmetic & Congruence, at your own pace.