3 fair coins are tossed. What is the probability of getting exactly two heads?

\frac{3}{16}

Correct answerYour answer

\frac{1}{4}

Correct answerYour answer

\frac{3}{8}

Correct answerYour answer

\frac{3}{7}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

There are $2^{3} = 8$ equally likely outcomes.
3 of them have exactly two heads, so the probability is $\frac{3}{8} = \frac{3}{8}$ .

Worth noting

Counting $4$ outcomes by the number of heads treats them as equally likely, and they are not.

Ten questions from Probability, at your own pace.

Explanation