Two fair dice are thrown. What is the probability that the sum is 7?

\frac{1}{11}

Correct answerYour answer

\frac{5}{36}

Correct answerYour answer

\frac{1}{6}

Correct answerYour answer

\frac{7}{36}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

There are $6 \times 6 = 36$ equally likely outcomes.
The sum is 7 in 6 of them: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1). So the probability is $\frac{6}{36} = \frac{1}{6}$ .

Worth noting

The 11 possible sums from 2 to 12 are not equally likely, so $\frac{1}{11}$ is wrong.

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Explanation