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Probability · Question 62 of 70

Question 62

MediumOriginal question

P(A)=0.7P(A) = 0.7, P(B)=0.4P(B) = 0.4 and P(A∪B)=0.85P(A \cup B) = 0.85. What is P(A∩B)P(A \cap B)?

Options for question 62

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. P(A∪B)=P(A)+P(B)−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B), so P(A∩B)=P(A)+P(B)−P(A∪B)P(A \cap B) = P(A) + P(B) - P(A \cup B).

  2. =0.7+0.4−0.85=0.25= 0.7 + 0.4 - 0.85 = 0.25.

Worth noting

0.28 multiplies 0.7×0.40.7 \times 0.4, which is right only for independent events; nothing here says they are.

Concept
The overlap from the addition rule
Typical time
90 s
Your time
—
The rule this testsThe addition and complement rules
Practise this chapter →

Ten questions from Probability, at your own pace.

Practise this chapter →

Ten questions from Probability, at your own pace.