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Probability · Question 33 of 70

Question 33

HardOriginal question

P(A)=0.6P(A) = 0.6 and P(B)=0.7P(B) = 0.7. What is the least possible value of P(A∩B)P(A \cap B)?

Options for question 33

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. P(A∪B)=P(A)+P(B)−P(A∩B)=1.3−P(A∩B)P(A \cup B) = P(A) + P(B) - P(A \cap B) = 1.3 - P(A \cap B).

  2. P(A∪B)≤1P(A \cup B) \le 1, so P(A∩B)≥0.3P(A \cap B) \ge 0.3: the events must overlap by at least 0.3.

Worth noting

0 would need P(A∪B)=1.3P(A \cup B) = 1.3, more than 1; 0.42 assumes the events are independent, which is not given.

Concept
Bounds from the axioms
Typical time
120 s
Your time
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The rule this testsThe rules every probability follows
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Ten questions from Probability, at your own pace.

Practise this chapter →

Ten questions from Probability, at your own pace.