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Three-Dimensional Geometry · Question 58 of 120

What is the image of P in L?

Question 58

HardOriginal question

A point P(5,1,4)P(5, 1, 4) and the line L:x−12=y2=z−3−1L: \frac{x - 1}{2} = \frac{y}{2} = \frac{z - 3}{-1} are given. MM is the point of LL with parameter λ\lambda, and FF is the foot of the perpendicular from PP to LL.

What is the image of PP in LL?

Options for question 58

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. FF is the midpoint of PP and its image P′P', so P′=2F−PP' = 2F - P.

  2. P′=(6−5,4−1,4−4)=(1,3,0)P' = (6 - 5, 4 - 1, 4 - 4) = (1, 3, 0).

Worth noting

(3,2,2)(3, 2, 2) is the foot FF, only halfway to the image.

Concept
The image of a point in a line
Typical time
150 s
Your time
—
The rule this testsThe equation of a line
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Ten questions from Three-Dimensional Geometry, at your own pace.

Practise this chapter →

Ten questions from Three-Dimensional Geometry, at your own pace.