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Three-Dimensional Geometry · Question 105 of 120

Match each line in List I with how it lies relative to L:

Question 105

MediumOriginal question

Match each line in List I with how it lies relative to L:r⃗=λ(2i^+j^)L: \vec{r} = \lambda(2\hat{i} + \hat{j}) in List II.

List IList II
A. r⃗=k^+μ(2i^+j^)\vec{r} = \hat{k} + \mu(2\hat{i} + \hat{j})I. Skew
B. r⃗=k^+μ(i^−2j^)\vec{r} = \hat{k} + \mu(\hat{i} - 2\hat{j})II. The same line
C. r⃗=k^+μ(2i^+j^−k^)\vec{r} = \hat{k} + \mu(2\hat{i} + \hat{j} - \hat{k})III. Parallel and distinct
D. r⃗=(4i^+2j^)+μ(−2i^−j^)\vec{r} = (4\hat{i} + 2\hat{j}) + \mu(-2\hat{i} - \hat{j})IV. Meeting at one point
Options for question 105

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. A has the direction of LL, and (0,0,1)(0, 0, 1) is not on LL: parallel and distinct. D has direction −(2i^+j^)-(2\hat{i} + \hat{j}) and passes through (4,2,0)(4, 2, 0), a point of LL: the same line.

  2. B and C are not parallel to LL. With a⃗2−a⃗1=k^\vec{a}_2 - \vec{a}_1 = \hat{k}, k^⋅(b⃗1×b⃗2)\hat{k} \cdot (\vec{b}_1 \times \vec{b}_2) is −5-5 for B, so B is skew, and 0 for C, which meets LL at (2,1,0)(2, 1, 0).

Concept
Classifying a pair of lines
Typical time
120 s
Your time
—
The rule this testsSkew lines and the shortest distance
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Ten questions from Three-Dimensional Geometry, at your own pace.

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Ten questions from Three-Dimensional Geometry, at your own pace.