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Vectors · Question 99 of 125

Question 99

MediumOriginal question

For which λ\lambda is (3i^−6j^+9k^)×(i^+λj^+3k^)=0⃗(3\hat{i} - 6\hat{j} + 9\hat{k}) \times (\hat{i} + \lambda\hat{j} + 3\hat{k}) = \vec{0}?

Options for question 99

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. The vector product is zero exactly when the vectors are parallel: 13=λ−6=39\frac{1}{3} = \frac{\lambda}{-6} = \frac{3}{9}.

  2. λ=−2\lambda = -2.

Worth noting

2 loses the sign: the j^\hat{j} part of the first vector is −6-6.

Concept
Parallel vectors and the vector product
Typical time
90 s
Your time
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The rule this testsThe vector product
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Ten questions from Vectors, at your own pace.

Practise this chapter →

Ten questions from Vectors, at your own pace.