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Counting and Basic Probability · Question 7 of 65

Question 7

MediumOriginal question

Four roads join Jaipur to Ajmer and three roads join Ajmer to Udaipur. Farhan drives from Jaipur to Udaipur through Ajmer and back again through Ajmer, and he does not use any road a second time. How many different round trips are possible?

Options for question 7

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Going: 4×3=124 \times 3 = 12 ways.

  2. Returning: one Udaipur–Ajmer road and one Ajmer–Jaipur road are already used, so 2×3=62 \times 3 = 6 ways.

  3. Round trips =12×6=72= 12 \times 6 = 72.

Worth noting

144 is 12×1212 \times 12, which allows a road to be reused. 12 counts only the outward journey.

Concept
Multiplication rule with a restriction on the return leg
Typical time
70 s
Your time
—
The rule this testsThe counting principle
Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.

Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.