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Counting and Basic Probability · Question 11 of 65

Question 11

MediumOriginal question

A restaurant's lunch offer is one main course from 4 choices together with EITHER one starter from 3 choices OR one dessert from 2 choices (not both). How many different lunches are possible?

Options for question 11

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Main with a starter: 4×3=124 \times 3 = 12 lunches.

  2. Main with a dessert: 4×2=84 \times 2 = 8 lunches.

  3. The two cases cannot overlap, so add: 12+8=2012 + 8 = 20.

Worth noting

24 is 4×3×24 \times 3 \times 2, which gives every lunch both a starter and a dessert. 12 counts only the starter case.

Concept
Combining the multiplication and addition rules
Typical time
70 s
Your time
—
The rule this testsThe counting principle
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