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Counting and Basic Probability · Question 18 of 65

Question 18

EasyOriginal question

Eight volunteers offer to help at a blood-donation camp, and the organiser needs a group of 3 of them. The 3 have identical duties. How many different groups can be chosen?

Options for question 18

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Order does not matter, so this is a combination.

  2. 8C3=8×7×63×2×1=3366=56{}^{8}C_{3} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = \frac{336}{6} = 56.

Worth noting

336 is 8P3{}^{8}P_{3}, which counts the same three people 6 times over, once for each order. 24 is 8×38 \times 3.

Concept
Combinations: unordered selection
Typical time
40 s
Your time
—
The rule this testsArrangements and selections
Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.

Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.