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Counting and Basic Probability · Question 17 of 65

Question 17

EasyOriginal question

Seven runners reach the final of a school 400 m race. In how many ways can the gold, silver and bronze medals be awarded, if no two runners tie?

Options for question 17

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Gold can go to any of 7 runners, silver to any of the other 6, bronze to any of the remaining 5.

  2. Ways =7×6×5=7P3=210= 7 \times 6 \times 5 = {}^{7}P_{3} = 210.

Worth noting

35 is 7C3{}^{7}C_{3}, which ignores which medal each runner gets. 343 is 737^3, which lets one runner win two medals.

Concept
Permutations: ordered selection
Typical time
40 s
Your time
—
The rule this testsArrangements and selections
Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.

Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.