Five friends, including Nikhil and Farah, sit in a row of 5 seats in random order. What is the probability that Nikhil and Farah get the two end seats?

Explanation

1. 01

   All seatings: $5! = 120$.

2. 02

   Nikhil and Farah at the ends: 2 ways (either can take the left end); the other three fill the middle in $3! = 6$ ways, giving 12.

3. 03

   Probability $= \frac{12}{120} = \frac{1}{10}$.