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Counting and Basic Probability · Question 65 of 65

Question 65

HardOriginal question

A standard deck has 52 cards in 4 suits of 13 (ace, 2 to 10, jack, queen, king); hearts and diamonds are red, clubs and spades are black, and the jack, queen and king are the face cards. Two cards are drawn together at random (without replacement). What is the probability that one is red and the other is black?

Options for question 65

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Ways to draw 2 cards: 52C2=1326{}^{52}C_{2} = 1326.

  2. One red and one black: 26×26=67626 \times 26 = 676.

  3. Probability =6761326=2651= \frac{676}{1326} = \frac{26}{51}.

Worth noting

12\frac{1}{2} is the answer WITH replacement (2×12×12)\left(2 \times \frac{1}{2} \times \frac{1}{2}\right). 2551\frac{25}{51} is P(same colour), and 1351\frac{13}{51} counts only the order red-then-black.

Concept
Mixed-colour draw without replacement
Typical time
120 s
Your time
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The rule this testsCoins, dice and cards
Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.

Practise this chapter →

Ten questions from Counting and Basic Probability, at your own pace.