PT is a tangent to a circle with centre O, touching it at T. If $\angle TOP = 58^\circ$, what is $\angle OPT$?

Explanation

1. 01

   The radius OT is perpendicular to the tangent, so $\angle OTP = 90^\circ$.

2. 02

   $\angle OPT = 180^\circ - 90^\circ - 58^\circ = 32^\circ$.