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Percentages · Question 65 of 72

Question 65

MediumOriginal question

A town has a population of 80,000. It increases by 10% in the first year and decreases by 5% in the second year. What is the population after 2 years?

Options for question 65

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. After year 1: 80000×1.1=88,00080000 \times 1.1 = 88{,}000.

  2. After year 2: 88000×0.95=83,60088000 \times 0.95 = 83{,}600.

Worth noting

84,000 uses 10−5=5%10 - 5 = 5\% on 80,000. The 5% fall is on 88,000, so it removes 4,400, not 4,000.

Concept
Growth and decline at different rates in different years
Typical time
50 s
Your time
—
The rule this testsPopulation growth and depreciation
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