Which is the second largest of $\frac{13}{16}, \frac{16}{19}, \frac{19}{22}$ and $\frac{22}{25}$?

Explanation

1. 01

   Each fraction is $1 - \frac{3}{\text{denominator}}$: $1 - \frac{3}{16}, 1 - \frac{3}{19}, 1 - \frac{3}{22}, 1 - \frac{3}{25}$.

2. 02

   The bigger the denominator, the smaller the part taken away, so the order is $\frac{13}{16} < \frac{16}{19} < \frac{19}{22} < \frac{22}{25}$.

3. 03

   The second largest is $\frac{19}{22}$.