What is the area of the region bounded by $y = \lvert x \rvert$ and $y = 2$?

Explanation

1. 01

   They meet at $x = \pm 2$; the line lies above: $\int_{-2}^{2} (2 - \lvert x \rvert)\,dx = 2\int_0^{2} (2 - x)\,dx$.

2. 02

   $2(4 - 2) = 4$ square units.