What is the area of the region between $x = 2y + 1$ , the $y$ -axis and the lines $y = 0$ and $y = 2$ ?

4 square unitsCorrect answerYour answer5 square unitsCorrect answerYour answer6 square unitsCorrect answerYour answer10 square unitsCorrect answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Horizontal strips: $\int_0^{2} (2y + 1)\,dy$ .
$\left[y^{2} + y\right]_0^{2} = 6$ square units.

Worth noting

4 integrates $2y$ alone, leaving out the strip of width 1.

Concept: Integrating along $y$
Typical timeTypical: 90 s
Your timeYours: —

The rule this testsRegions with lines

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What is the area of the region between x=2y+1x = 2y + 1x=2y+1, the yyy-axis and the lines y=0y = 0y=0 and y=2y = 2y=2?

Explanation

What is the area of the region between $x = 2y + 1$ , the $y$ -axis and the lines $y = 0$ and $y = 2$ ?