What is the area enclosed by the ellipse $x^{2} + 4y^{2} = 16$?

Explanation

1. 01

   In standard form $\frac{x^{2}}{16} + \frac{y^{2}}{4} = 1$, so $a = 4$, $b = 2$.

2. 02

   Area $= \pi ab = 8\pi$ square units.