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Area of Bounded Regions · Question 104 of 115

Question 104

MediumOriginal question

Assertion (A): The ellipse x216+y29=1\frac{x^{2}}{16} + \frac{y^{2}}{9} = 1 and the circle x2+y2=12x^{2} + y^{2} = 12 enclose equal areas.

Reason (R): The area enclosed by x2a2+y2b2=1\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 is πab\pi ab.

Options for question 104

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. R: 4ba∫0aa2−x2 dx=πab\frac{4b}{a}\int_0^{a} \sqrt{a^{2} - x^{2}}\,dx = \pi ab. True.

  2. So the ellipse encloses π×4×3=12π\pi \times 4 \times 3 = 12\pi, and the circle, the case a=b=12a = b = \sqrt{12}, encloses 12π12\pi: A is true, and R explains it.

Worth noting

Doubting A compares 16 and 9 with 12; the areas depend on ab=12ab = 12 and on the square of the radius, also 12.

Concept
Comparing two areas
Typical time
90 s
Your time
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The rule this testsEllipses
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Ten questions from Area of Bounded Regions, at your own pace.

Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.