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Area of Bounded Regions · Question 18 of 115

Question 18

MediumOriginal question

Assertion (A): The area enclosed by ∣x∣+∣y∣=3\lvert x \rvert + \lvert y \rvert = 3 is 18 square units.

Reason (R): The region ∣x∣+∣y∣≤3\lvert x \rvert + \lvert y \rvert \le 3 is symmetric about both axes, and its part in the first quadrant is the triangle bounded by x+y=3x + y = 3 and the axes.

Options for question 18

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. In the first quadrant ∣x∣+∣y∣=3\lvert x \rvert + \lvert y \rvert = 3 is x+y=3x + y = 3, and ∫03(3−x) dx=92\int_0^{3} (3 - x)\,dx = \frac{9}{2}. R is true.

  2. By that symmetry the area is 4×92=184 \times \frac{9}{2} = 18: A is true, and R is the reason.

Worth noting

The first-quadrant triangle alone is 92\frac{9}{2}; the symmetry in R is what multiplies it by 4.

Concept
Using symmetry
Typical time
90 s
Your time
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The rule this testsRegions with lines
Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.

Practise this chapter →

Ten questions from Area of Bounded Regions, at your own pace.