What is the area of Q?

Explanation

1. 01

   In the first quadrant the side of $Q$ is $\frac{x}{6} + \frac{y}{4} = 1$, that is $y = 4 - \frac{2x}{3}$: $\int_0^{6} \left(4 - \frac{2x}{3}\right)dx = 24 - 12 = 12$.

2. 02

   $Q$ is symmetric about both axes: $4 \times 12 = 48$ square units, half of $12 \times 8$.