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Conditional Probability & Bayes' Theorem · Question 1 of 125

Question 1

EasyOriginal question

P(A)=35P(A) = \frac{3}{5}, P(B)=12P(B) = \frac{1}{2} and P(A∩B)=310P(A \cap B) = \frac{3}{10}. What is P(A∣B)P(A \mid B)?

Options for question 1

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. P(A∣B)=P(A∩B)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)}, and P(A′∣B)=1−P(A∣B)P(A' \mid B) = 1 - P(A \mid B).

  2. P(A∣B)=31012=35P(A \mid B) = \frac{\frac{3}{10}}{\frac{1}{2}} = \frac{3}{5}.

Worth noting

310\frac{3}{10} is P(A∩B)P(A \cap B) itself, before dividing by P(B)P(B).

Concept
Conditional probability from given probabilities
Typical time
60 s
Your time
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The rule this testsConditional probability
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.