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Conditional Probability & Bayes' Theorem · Question 22 of 125

Question 22

MediumOriginal question

For events AA and BB with P(A)>0P(A) > 0 and P(B)>0P(B) > 0, which of the following statements are true?

I. If A⊂BA \subset B, then P(B∣A)=1P(B \mid A) = 1.

II. If A⊂BA \subset B, then P(A∣B)=P(A)P(B)P(A \mid B) = \frac{P(A)}{P(B)}.

III. If AA and BB are mutually exclusive, then P(A∣B)=0P(A \mid B) = 0.

IV. P(A∣B)≥P(A)P(A \mid B) \ge P(A) for any two such events.

Options for question 22

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. I: A∩B=AA \cap B = A, so P(B∣A)=P(A)P(A)=1P(B \mid A) = \frac{P(A)}{P(A)} = 1. II: P(A∣B)=P(A∩B)P(B)=P(A)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)} = \frac{P(A)}{P(B)}. III: P(A∩B)=0P(A \cap B) = 0, so P(A∣B)=0P(A \mid B) = 0.

  2. IV is false: for mutually exclusive events P(A∣B)=0P(A \mid B) = 0, which is less than P(A)P(A).

Worth noting

A condition can lower a probability as well as raise it.

Concept
Properties of conditional probability
Typical time
120 s
Your time
—
The rule this testsConditional probability
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.