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Conditional Probability & Bayes' Theorem · Question 36 of 125

Question 36

EasyOriginal question

Two cards are drawn one after the other, without replacement, from a well-shuffled pack of 52. What is the probability that they are of the same suit?

Options for question 36

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. The first card can be any card; 12 of the 51 cards left share its suit.

  2. 1×1251=4171 \times \frac{12}{51} = \frac{4}{17}.

Worth noting

14\frac{1}{4} puts the first card back; without replacement only 12 cards of its suit remain among 51.

Concept
Probabilities without replacement
Typical time
60 s
Your time
—
The rule this testsThe multiplication theorem
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.