$P(A) = 0.7$ and $P(B \mid A) = 0.4$. What is $P(A \cap B')$?

Explanation

1. 01

   Given $A$, $P(B' \mid A) = 1 - 0.4 = 0.6$.

2. 02

   $P(A \cap B') = P(A)\,P(B' \mid A) = 0.7 \times 0.6 = 0.42$.