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Conditional Probability & Bayes' Theorem · Question 63 of 125

Question 63

MediumOriginal question

AA and BB are independent with P(A)=0.3P(A) = 0.3 and P(B)=0.6P(B) = 0.6. What is the probability that exactly one of them happens?

Options for question 63

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. AA only: 0.3×0.4=0.120.3 \times 0.4 = 0.12; BB only: 0.7×0.6=0.420.7 \times 0.6 = 0.42.

  2. 0.12+0.42=0.540.12 + 0.42 = 0.54.

Worth noting

0.72 is at least one, 1−0.7×0.41 - 0.7 \times 0.4, which also counts both happening.

Concept
Probabilities with independent events
Typical time
90 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.