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Conditional Probability & Bayes' Theorem · Question 64 of 125

Question 64

MediumOriginal question

Read the two statements and choose the correct option.

I. A number is picked at random from 1 to 10. The events EE: the number is even, and MM: the number is a multiple of 3, are independent.

II. A number is picked at random from 1 to 12. The events EE: the number is even, and MM: the number is a multiple of 3, are independent.

Options for question 64

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. I: P(E)=12P(E) = \frac{1}{2}, P(M)=310P(M) = \frac{3}{10} and E∩M={6}E \cap M = \{6\}: 110≠12×310\frac{1}{10} \ne \frac{1}{2} \times \frac{3}{10}. False.

  2. II: P(E)=12P(E) = \frac{1}{2}, P(M)=13P(M) = \frac{1}{3} and E∩M={6,12}E \cap M = \{6, 12\}: 212=16=12×13\frac{2}{12} = \frac{1}{6} = \frac{1}{2} \times \frac{1}{3}. True.

Worth noting

Independence is a fact about the numbers, not about how the events are described: the same two events are independent on 1 to 12 but not on 1 to 10.

Concept
Testing for independence
Typical time
90 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.