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Conditional Probability & Bayes' Theorem · Question 71 of 125

Question 71

HardOriginal question

Two dice are thrown. AA: the first die shows an even number. BB: the sum is 7. Are AA and BB independent?

Options for question 71

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. P(A)=12P(A) = \frac{1}{2}, P(B)=636=16P(B) = \frac{6}{36} = \frac{1}{6}, and A∩B={(2,5),(4,3),(6,1)}A \cap B = \{(2, 5), (4, 3), (6, 1)\}, so P(A∩B)=336=112P(A \cap B) = \frac{3}{36} = \frac{1}{12}.

  2. 12×16=112\frac{1}{2} \times \frac{1}{6} = \frac{1}{12}: independent.

Worth noting

Whatever the first die shows, exactly one value of the second makes 7, so knowing AA does not change the chance of BB.

Concept
Testing for independence
Typical time
120 s
Your time
—
The rule this testsIndependent events
Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.