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Conditional Probability & Bayes' Theorem · Question 92 of 125

Question 92

MediumOriginal question

One card is lost from a well-shuffled pack of 52. A card is then drawn at random from the remaining 51. What is the probability that it is a heart?

Options for question 92

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Split on the lost card: a heart with probability 1352\frac{13}{52}, leaving 12 hearts; not a heart with probability 3952\frac{39}{52}, leaving 13.

  2. 1352×1251+3952×1351=156+5072652=14\frac{13}{52} \times \frac{12}{51} + \frac{39}{52} \times \frac{13}{51} = \frac{156 + 507}{2652} = \frac{1}{4}.

Worth noting

417=1251\frac{4}{17} = \frac{12}{51} assumes the lost card was a heart, which is only one of the two cases.

Concept
The theorem of total probability
Typical time
90 s
Your time
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The rule this testsThe theorem of total probability
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.