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Conditional Probability & Bayes' Theorem · Question 91 of 125

What is the probability that the ball drawn from bag II is red?

Question 91

MediumOriginal question

Bag I has 3 red and 2 black balls; bag II has 2 red and 3 black balls. One ball is drawn at random from bag I and put into bag II without its colour being seen. Then a ball is drawn at random from bag II.

What is the probability that the ball drawn from bag II is red?

Options for question 91

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Split on the ball moved: P(R)=35×36+25×26P(R) = \frac{3}{5} \times \frac{3}{6} + \frac{2}{5} \times \frac{2}{6}.

  2. 930+430=1330\frac{9}{30} + \frac{4}{30} = \frac{13}{30}.

Worth noting

25\frac{2}{5} is bag II's share of red before the move; the ball moved in changes it.

Concept
The theorem of total probability
Typical time
120 s
Your time
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The rule this testsThe theorem of total probability
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.