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Conditional Probability & Bayes' Theorem · Question 119 of 125

Question 119

HardOriginal question

Box I has 2 white and 3 black balls; box II has 4 white and 1 black. A box is picked at random and the ball drawn from it is white. What is the probability that it came from box II?

Options for question 119

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. P(W)=12×25+12×45=35P(W) = \frac{1}{2} \times \frac{2}{5} + \frac{1}{2} \times \frac{4}{5} = \frac{3}{5}.

  2. P(II∣W)=12×4535=23P(\text{II} \mid W) = \frac{\frac{1}{2} \times \frac{4}{5}}{\frac{3}{5}} = \frac{2}{3}.

Worth noting

35\frac{3}{5} is P(W)P(W), the chance of white at all; Bayes divides by it.

Concept
Bayes' theorem
Typical time
120 s
Your time
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The rule this testsBayes' theorem
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.