Two dice are thrown. Given that they show different numbers, what is the probability that the sum is 6?

\frac{1}{9}

Correct answerYour answer

\frac{2}{15}

Correct answerYour answer

\frac{5}{36}

Correct answerYour answer

\frac{1}{6}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

Different numbers: $36 - 6 = 30$ outcomes.
Sum 6 with different numbers: $(1, 5), (5, 1), (2, 4), (4, 2)$ , so $\frac{4}{30} = \frac{2}{15}$ .

Worth noting

$\frac{5}{36}$ ignores the condition: it keeps $(3, 3)$ and divides by all 36 outcomes.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Explanation