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Conditional Probability & Bayes' Theorem · Question 113 of 125

Question 113

HardOriginal question

Bag I has 3 red and 4 black balls; bag II has 5 red and 4 black. A bag is picked at random and the ball drawn from it is red. What is the probability that it came from bag II?

Options for question 113

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. P(II∣R)=P(II)P(R∣II)P(R)=12⋅593163P(\text{II} \mid R) = \frac{P(\text{II})P(R \mid \text{II})}{P(R)} = \frac{\frac{1}{2} \cdot \frac{5}{9}}{\frac{31}{63}}.

  2. 518×6331=3562\frac{5}{18} \times \frac{63}{31} = \frac{35}{62}.

Worth noting

59\frac{5}{9} is P(R∣II)P(R \mid \text{II}), the chance the other way round.

Concept
Bayes' theorem
Typical time
120 s
Your time
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The rule this testsBayes' theorem
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.